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Add summary statistic to histogram in R

I am using the hist() function to plot a histogram. How can I add a summary statistic for each bin? I am only able to plot this summary statistic across the entire distribution.

A:

You may want to first calculate your summary and then create the histogram with this summary as the y-value of each bin.
You can use the field name summary.stats from your histsum object.
#Sample data
hist.s Jakub Orliński

Jakub Orliński (born 18 July 1990 in Oświęcim) is a Polish footballer.

Career
Orliński made his Ekstraklasa debut on 19 August 2009 in a 1–2 loss away to Czarni Radom. He was an unused substitute in the first team in the 2010–11 season.

Honours

Club
GKS Katowice
Polish Cup: 2008–09, 2010–11

References

External links

Category:1990 births
Category:Living people
Category:Polish footballers
Category:Stomil Olsztyn players
Category

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Counting possible variations of a game

I’m trying to simulate an idea I had for a card game. In short, every player can create a deck out of ten cards. Each player will hold a combined 15 cards and the points earned are based on how many variations you can create with those cards. For the cards to be combined they have to have a difference of at least one (not including colour, suit, or position of the rank).
I’m trying to figure out a way to calculate the maximum number of variations that could be created by twenty people to see what variations occur the most.
Can anyone tell me an algorithm to calculate this? Is there a name to this type of problem? I know it would help a lot if it was written down or described somewhere. I’m not sure if I’m looking for a name I’m looking for a description of it.

A:

Let $x_i$ be the number of variations that can be created with the deck of player $i$ (for $i\in\{1,2,3\ldots,20\}$).
Then your problem is equivalent to finding the average:
$$\frac{x_1+x_2+\ldots+x_{20}}{20}$$
Multiplying all the $x_i$ together and dividing by $20$ gives the best answer you can hope to get for the average.
An easy way to calculate $x_1$ is to choose the $10$ cards from a standard deck of $52$ cards. Then $x_1=52$ possibilities. The other $x_i$ are calculated similarly, but now you only have $15$ decks of cards to choose from.
The total number of possibilities is $52^{20}=259573762894671064819284950746512725692012918933360$

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